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Monday, 22 June 2020

conservation energy/pulley problem!!!?

Dorris Homola: conservation of energy:mgh = ½Iω²(rotational k.e) + ½mv² (linear kinetic energy) + ½kx² (spring potential)=> mgh = ½I(v/r)²(rotational k.e) + ½mv² (linear kinetic energy) + ½kx²=> 4(9.81)0.15 = ½*½5v² + ½4v² + 50(0.15)²=> 3.25v² = 4.761or v ~= 1.21 m/shope this helps...Show more

Vern Serratos: X= 1.5M !

Salvador Prchlik: i did solve it, just wanna know if i did anything wrong.!

Ronald Moehr: i ment x is 0.15m not 0.1m!and I = 1/2mr^2

Lynn Melbourne: Do your homework

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